Round intermediate values, producing a distractor-matching final answer.
An error-pattern drill: practice spotting and avoiding this specific SHSAT trap.
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In a sample, 14 of 30 students walk to school. About how many of 1,500 students walk? If you round \(14 \div 30 \approx 0.47\) up to 0.5 first, you get \(0.5 \times 1500 = 750\). The exact answer is \(\tfrac{14}{30} \times 1500 = 700\). One early rounding made the answer off by 50.
Students round early because long decimals feel messy. But the error grows when you multiply by a big number, and the test often puts that wrong number in the choices.
Check habits:
Sample proportion = 26 \(\div\) 30. Apply it to the full population: 26 \(\div\) 30 \(\times\) 1110 = 962. (Adding the difference instead of scaling (\(26 + (1110 - 30)\)) gives 1106. Rounding 26 \(\div\) 30 to 0.9 before multiplying (\(0.9 \times 1110\)) gives 999. Stopping at the scale factor (\(1110 \div 30\)) gives 37.)
Multiply the exact values: \(47 \times 39 = 1833\). Rounding both numbers to the nearest ten first (50 and 40) gives \(2000\). Rounding only 47 (to 50) gives \(1950\). Rounding only 39 (to 40) gives \(1880\).
Sample proportion = 21 \(\div\) 60. Apply it to the full population: 21 \(\div\) 60 \(\times\) 600 = 210. (Adding the difference instead of scaling (\(21 + (600 - 60)\)) gives 561. Rounding 21 \(\div\) 60 to 0.4 before multiplying (\(0.4 \times 600\)) gives 240. Stopping at the scale factor (\(600 \div 60\)) gives 10.)