Solve for x but stop before computing the quantity actually asked (e.g., x+2).
An error-pattern drill: practice spotting and avoiding this specific SHSAT trap.
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Solve \(3x - 4 = 11\) and find \(x + 2\). You get \(x = 5\), and 5 is one of the answer choices. But the question asks for \(x + 2\), so the answer is 7.
Test writers put the halfway number in the choices on purpose. When you see your number there, it feels like proof that you are done. Word problems do this a lot: you find \(x\), but the question asks for a length, a sum, or the other number.
Check habits:
Vertical angles are equal, so \(2x + 16 = 3x - 41\), which gives \(x = 57\). Each angle \(= 2(57) + 16 = 130^\circ\). (Stopping at \(x = 57\) gives 57, not the angle. Finding the angle next to it, \(180 - 130\), gives \(50^\circ\). Setting the two expressions to add to \(180^\circ\) gives \(x = 41\) and an angle of \(98^\circ\).)
Let the integers be \(n, n+1, n+2\). Their sum is \(3n + 3 = 21\), so \(n = 6\). The integers are 6, 7, 8. The sum of the smallest and largest is 14. (Stopping at \(n\) gives \(6\). Adding all three integers gives \(21\). Adding the smallest and the middle integers gives \(13\).)
A triangle's angles add to \(180^\circ\), so the third angle \(= 180 - 48 - 79 = 53^\circ\). (Stopping at \(48 + 79\) gives \(127^\circ\). Subtracting from \(360^\circ\) instead gives \(233^\circ\). Subtracting only 48 from 180 gives \(132^\circ\).)