Report the mean when the median is asked, or vice versa.
An error-pattern drill: practice spotting and avoiding this specific SHSAT trap.
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The mean and the median are both called an "average", and the trap answer is usually the other one.
The two values are far apart here because 15 is an outlier. An outlier pulls the mean toward it, but it moves the median very little. Test writers put both values in the choices.
Check habits:
Mean = sum \(\div\) count = 189 \(\div\) 7 = 27. (Reporting the median (the middle of 14, 15, 24, 29, 30, 35, 42) gives 29. Dividing by 6 instead of 7 (\(189 \div 6\)) gives 31.5. Averaging only the largest and smallest scores (\((42 + 14) \div 2\)) gives 28.) The mean score is 27.
| Stem | Leaves |
|---|---|
| 1 | 2 4 |
| 2 | 5 7 8 |
| 3 | 2 4 5 |
| 4 | 3 3 3 9 |
Reading off the leaves gives the sorted scores: 12, 14, 25, 27, 28, 32, 34, 35, 43, 43, 43, 49. With 12 scores, the median is the average of the two middle scores: (32 + 34) \(\div\) 2 = 33. (Reporting the mean (\(385 \div 12\)) gives about 32.08. Adding the two middle scores but not dividing by 2 (\(32 + 34\)) gives 66. Using only the lower of the two middle scores gives 32.) The median score is 33.
Average speed \(=\) total distance \(\div\) total time, NOT the average of the leg speeds. Total distance \(= 27 + 133 = 160\) mi. Total time \(= 1.5 + 150 \div 60 = 4\) h. Average speed \(= 160 \div 4 = 40\) mph. (Averaging the two leg speeds gives 35.6 mph. Writing 150 minutes as 1.5 hours (\(160 \div (1.5 + 1.5)\)) gives about 53.3 mph. Using the first leg's speed only (\(27 \div 1.5\)) gives 18 mph.)