Proportional relationships & graphs drills

Recognize proportional relationships as straight lines through the origin; read k from a graph.

Free, timed SHSAT practice sets on proportional relationships & graphsβ€” every question includes a full worked explanation, and there's no account required.

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How to solve proportional relationship graph problems

A proportional relationship always graphs as a straight line through the origin \((0, 0)\). A straight line that misses the origin is not proportional.

Common traps:

Worked examples

Example 1.
The graph of a proportional relationship is a straight line through the origin that also passes through the point \((10, 58)\). What is the constant of proportionality \(k\) for this line (where \(y = kx\))?
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Answer:
C

For a line through the origin, \(k = y \div x = 58 \div 10 = 5.8\). (Dividing \(x\) by \(y\) reads the point on the wrong axis and gives about 0.172. Using the \(y\)-coordinate itself gives 58. Subtracting, \(58 - 10\), gives 48.)

Example 2.
A proportional relationship's graph is a straight line through the origin that passes through \((6, 9)\). What \(y\)-value does the line pass through when \(x = 15\)?
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Answer:
D

\(k = 9 \div 6 = 1.5\), so at \(x = 15\), \(y = 1.5 \times 15 = 22.5\). (Using \(6 \div 9\) as the rate gives 10. Adding the change in \(x\), \(9 + 9\), gives 18. Multiplying \(9 \times 15\) without dividing by 6 gives 135.)