Combine two ratios or relationships that share a common quantity (a:b and b:c) into a single ratio, or use the combined relationship to split a total.
Free, timed SHSAT practice sets on combining ratios via a shared quantityβ every question includes a full worked explanation, and there's no account required.
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When two ratios share a quantity (a:b and b:c), make the shared quantity the same number in both ratios. Then join them.
Example: cats to dogs is \(3:4\) and dogs to birds is \(6:5\). Dogs are 4 and 6, and \(\text{LCM}(4, 6) = 12\). So \(3:4 = 9:12\) and \(6:5 = 12:10\). Cats to dogs to birds is \(9:12:10\).
To split a total, use the combined ratio. If there are 62 animals: \(9 + 12 + 10 = 31\) parts, one part is \(62 \div 31 = 2\), so there are \(9 \times 2 = 18\) cats.
Common trap: joining the raw numbers as \(3:4:5\). That is wrong, because the dogs are 4 in one ratio and 6 in the other.
The shared term is second graders: scale 6:5 by 4 and 4:3 by 5 so both give second graders \(= 20\) (the LCM of 5 and 4). This gives 24:20:15, which is already in lowest terms. (Joining the original numbers without matching second graders gives 6:5:3 or 6:4:3. Writing 20 for second graders but swapping the factors on the outer terms (\(6 \times 5\) and \(3 \times 4\)) gives 30:20:12, which reduces to 15:10:6.)
Combining via the shared oatmeal cookies term gives chocolate cookies:oatmeal cookies:sugar cookies \(= 8:12:15\), so chocolate cookies \(= 105 \times 8 \div 35 = 24\). (Splitting with the unmatched numbers 2:3:5 gives 21. Finding the oatmeal cookies instead gives 36. Using only 2:3 and ignoring the sugar cookies, \(105 \times 2 \div 5\), gives 42.)